Ответы
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1)X^2+3x=0X(x+3)=0X=0X+3=oX=-32)x^2-4x-5=0D=(-4)^2-4*1*(-5)=36x1,2 = (4+-√36) / 2 = (4+-6) / 2 = 2+-3x1 = 2-3 = -1,x2 = 2+3 = 5.
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1)X^2+3x=0X(x+3)=0X=0X+3=oX=-32)x^2-4x-5=0D=(-4)^2-4*1*(-5)=36x1,2 = (4+-√36) / 2 = (4+-6) / 2 = 2+-3x1 = 2-3 = -1,x2 = 2+3 = 5.